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SAT Math 9.3 Geometry and Measurement 194 Views
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Description:
SAT Math 9.3 Geometry and Measurement
Transcript
- 00:03
Here’s your shmoop du jour, brought to you by bugs. Not the rabbit kind.
- 00:09
A square with side lengths of square root of 2 is circumscribed into a circle.
- 00:14
A bug, traveling along the perimeter of the circle, moves from Point K to Point H.
- 00:20
How far did the bug travel?
- 00:22
Here are the potential answers...
Full Transcript
- 00:26
All right, so we’ve got a bug on the move.
- 00:29
Any time we have a problem like this, we should be thinking in terms of a full circle.
- 00:33
In other words, we’re probably not going to be able to find the exact measure of just this little arc…
- 00:38
…without first finding the circumference of the entire circle…
- 00:41
…and then just taking 1/4 of that.
- 00:45
So…how do we find the circumference of the circle?
- 00:48
Well, first, we need the diameter. If we draw a line from H to J we get one…
- 00:55
now we just need to find its value…
- 00:57
Because we’re dealing with a square, we know we have right angles,
- 01:00
and the other two angles of our new triangle must be equal.
- 01:05
So…we’ve got a 45-45-90 triangle…sweet.
- 01:10
45-45-90 triangles have side lengths with a ratio of x to x to x square root of 2…
- 01:16
…so, if we’re taking the square root of 2 times the square root of 2, we wind up with just… plain ol’ 2.
- 01:21
So yeah, that's our diameter... 2.
- 01:24
Now all we have to do is plug that into our circumference formula of pi times the diameter…
- 01:29
…and we get 2 pi.
- 01:30
One-fourth of that is 1/2 pi… which is choice B.
- 01:34
As in, “Bugged.”
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