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Yeah Whoa Okay SCT mash members Next up more circles

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for you The figure above shows a circular running track

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like her horses probably The distance from the center of

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the track to the bleachers is thirty nine yards and

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the distance from the edge of the track The bleachers

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is four yards Which falling equations accurately models the running

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track if the bleachers are set at zero zero So

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let's think about this Well to hit the ground running

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with this problem start by labeling the figure using the

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given measurements And that's how it works Right Like that

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Split that thirty nine yards segment into two segments breaking

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it at the point where it touches the edge of

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the circle there And yeah that looks right Thirty five

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and four All right the radius of the circles Thirty

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five Keep in mind the standard form of a circle

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X minus H Y minus K R Yeah Okay And

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H K is the centre right That's the X and

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y coordinate center Well there's no horizontal shift so H

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is zero and K is the vertical coordinate of the

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center point Which means it's the why distance from the

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origin which is zero zero right OK is the distance

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from the bleachers to the centre here which is thirty

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nine We also have to be careful with signs This

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why value is a positive thirty nine So plugging it

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in for K makes that term look like this Why

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minus thirty nine quantity squared Well finally R squared goes

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on the right side of the equation And here that's

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thirty five squared which is twelve twenty five Giving us

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X squared plus quantity Y minus thirty nine quantity squared

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equals twelve twenty five That's the equation of circle Its 00:01:27.79 --> [endTime] answer C lovely Have a fun run

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