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TSI Math: Working Backwards from the Midpoint Formula to Find an Endpoint 13 Views
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Description:
Point B is the midpoint of segment AC. The coordinates of A are (-9, 3) and the coordinates of B are (2, -3). What are the coordinates of C?
Point B is the midpoint of segment AC. The coordinates of A are (-9, 3) and the coordinates of B are (2, -3). What are the coordinates of C?
Transcript
- 00:03
Okay yes i mash bumpers another one up for you
- 00:06
On the coordinate plane point b is the midpoint of
- 00:08
segment A c coordinates of a r negative nine Three
- 00:12
The coordinates of b r two Negative three one of
- 00:15
coordinates of c We'll be is in the middle of
Full Transcript
- 00:20
a c right there That's Why it's the midpoint Consider
- 00:23
the x and y coordinates separately So the ex coordinative
- 00:27
et is negative Nine The exporting and b is two
- 00:29
there's a horizontal distance They're of two minus negative nine
- 00:33
or eleven units between two points If we moved another
- 00:37
eleven units to the right well then we'd arrive at
- 00:39
the x coordinate of c rights We have two plus
- 00:43
eleven and thirteen so the x coordinate of sea is
- 00:46
thirteen So well now we'll do the same thing with
- 00:49
the y coordinates and get a cz Why coordinate up
- 00:52
three there Two b's Why coordinate of negative three We
- 00:55
need to move down three minus three that six units
- 00:59
moving over six units down to arrive at the negative
- 01:02
three months Six Well that's negative nine So sees why
- 01:05
coordinate their so put x and y coordinates back together
- 01:09
and we see that sea is located at the point
- 01:11
Thirteen negative nine and a is the answer Yeah we're 00:01:15.972 --> [endTime] shmoop
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